Complex analysis: laurent, residues

In summary, the Laurent theorem states that for an analytic function f in an annular domain centered at z0, f can be represented by a series consisting of an infinite sum of coefficients an and bn. These coefficients can be calculated using the Cauchy Residue Theorem and the integral of a closed contour around the singularities. However, the value of bn may not necessarily be equal to the residue of f at z0, depending on the radius of the annular domain. It is important to note that the Laurent series can be different in the neighborhood of each singularity.
  • #1
shakeydakey
4
0
This is addressed to people who know complex analysis (hope this is the right section). Here's the Laurent theorem from my book for my later reference: Suppose a function f is analytic throughout an annular domain R1<|z-z0|<R2, centered at z0, and let C denote any positively oriented simple closed contour around z0 and lying in that domain. Then, at each point in the domain, f(z) has the series representation f(z)=sum (n=0 to inf) of an(z-z0) + sum(n=1 to inf) bn/(z-z0)^n, where an=(1/ 2pi*i) integral over C of f(z)dz/(z-z0)^(n+1) and bn=(1/ 2pi i) integral over C of f(z)dz/(z-z0)^(-n+1).

So say there is a finite number of singularities of f, so they're all in a circle of some radius R. It seems to me you could select any point p in the complex plane, and then make an annulus around that point such that its inner perimeter encloses the singularities. The theorem seems to say that 2pi i *Res(f,p) is equal to the integral of a closed contour around the singularities. I know this is wrong b/c it doesn't agree with what I've seen with the Cauchy Residue Thm, where I calculated that integral by summing residues at singularities. Where is the disconnect?
 
Physics news on Phys.org
  • #2
Good question.

b1 is not necessarily Res(f,z0) if the Laurent expansion is for R1<|z-z0|<R2 with R1>0.

If the Laurent expansion is for 0<|z-z0|<R2, then b1=Res(f,z0).
 
  • #3
i don't understand what billy bob said and i don't understand what you said.

residue theorem says the integral over a closed contour of f(z)/z-z0= res(f,z0) where the residue is the coefficient of the 1/z term in the laurent expansion. a corollary of cauchy goursat theorem states that if a function is analytic in some domain and contour encloses another contour the then integrals around those contours are equal. extending that a little and you get that the integral around a contour containing other contours equals the sum of integrals around each contour. this is why the integral of a function with several singularities around a contour equals the sum of the residues.

note that the laurent series is different in the neighborhood around each singularity.
 

What is complex analysis?

Complex analysis is a branch of mathematics that deals with the study of functions of complex numbers. It involves the study of their properties, behavior, and relationships, and is an important tool in many areas of mathematics and science.

What is the Laurent series?

The Laurent series is a way of representing a complex function as an infinite sum of terms, each containing a power of the complex variable raised to a negative integer. It is used to analyze the behavior of functions near singularities, and can also be used to approximate functions in a certain region.

What are residues in complex analysis?

In complex analysis, residues refer to the values of a function at its singular points, or poles. They are important in the study of complex functions, as they can provide information about the behavior of a function near its singularities.

How are residues calculated?

Residues can be calculated using the Cauchy integral formula, which relates the value of a function at a point inside a closed contour to the values of the function and its derivatives at points inside the contour. The residue can be found by evaluating this formula at the singular point of the function.

What are the applications of complex analysis?

Complex analysis has many applications in mathematics and science, including physics, engineering, and economics. It is used to solve problems in potential theory, fluid dynamics, signal processing, and many other fields. It also has applications in computer graphics and image processing.

Similar threads

Replies
7
Views
1K
Replies
3
Views
1K
  • Calculus
Replies
8
Views
2K
Replies
4
Views
1K
Replies
21
Views
2K
Replies
2
Views
790
  • Calculus and Beyond Homework Help
Replies
3
Views
868
Back
Top