Engineering Complex Diode Circuit: Solve DC Output, Ripple, Rating & Power

Click For Summary
SUMMARY

The discussion revolves around analyzing a power supply circuit involving diodes with a forward voltage drop of 0.6V. Key tasks include determining the DC output voltage under no load, calculating ripple amplitude at a 200mA load, establishing the current rating to maintain ripple below 1% of output voltage, and finding average power dissipation at ω = 300 rad/s. The approach emphasizes converting RMS voltage to peak-to-peak AC voltage and understanding the relationship between AC input and DC output through the bridge rectifier.

PREREQUISITES
  • Understanding of diode characteristics, specifically forward voltage drop.
  • Knowledge of transformer voltage types, particularly RMS (root mean square).
  • Familiarity with bridge rectifier operation and its impact on output voltage.
  • Basic principles of power calculations in electrical circuits.
NEXT STEPS
  • Learn how to convert RMS voltage to peak-to-peak voltage in AC circuits.
  • Study the principles of ripple voltage in power supply design.
  • Investigate current rating calculations for power supplies to minimize ripple.
  • Explore average power dissipation formulas in electronic circuits.
USEFUL FOR

Electronics students, electrical engineers, and hobbyists working on power supply design and analysis, particularly those focusing on diode circuits and ripple calculations.

rx78
Messages
2
Reaction score
0

Homework Statement



Consider the following power supply circuit, which uses typical component values. The
diodes have a forward drop of 0.6V each. Transformer voltages are RMS (root mean
square).

http://img294.imageshack.us/img294/1665/70454661.png

a. Determine the DC output voltage under ‘no load’.
b. Determine the amplitude of the ripple when a current of 200mA is drawn from the
supply.
c. What should the current “rating” of the supply be, if the ripple (peak-to-peak)
must be kept below 1% of the output voltage?
d. Find the average power dissipated in the circuit assuming ω = 300 rad/s.

Homework Equations



unsure...

The Attempt at a Solution



Honestly, I'm just not really sure where to actually -start- on this. We barely touched on this material in class and our text (Principles of Electronics Analog and Digital) is fairly lacking in any sort of examples to try to follow the logic. I just need some tips on how to approach this problem from a fundamental standpoint, really, so if you can just give some tips on how to start with it, I can probably carry on.
 
Last edited by a moderator:
Physics news on Phys.org
rx78 said:

Homework Statement



Consider the following power supply circuit, which uses typical component values. The
diodes have a forward drop of 0.6V each. Transformer voltages are RMS (root mean
square).

http://img294.imageshack.us/img294/1665/70454661.png

a. Determine the DC output voltage under ‘no load’.
b. Determine the amplitude of the ripple when a current of 200mA is drawn from the
supply.
c. What should the current “rating” of the supply be, if the ripple (peak-to-peak)
must be kept below 1% of the output voltage?
d. Find the average power dissipated in the circuit assuming ω = 300 rad/s.

Homework Equations



unsure...

The Attempt at a Solution



Honestly, I'm just not really sure where to actually -start- on this. We barely touched on this material in class and our text (Principles of Electronics Analog and Digital) is fairly lacking in any sort of examples to try to follow the logic. I just need some tips on how to approach this problem from a fundamental standpoint, really, so if you can just give some tips on how to start with it, I can probably carry on.

First, convert the output RMS voltage number to a peak-to-peak AC voltage number. That is the input waveform to the bridge. Then figure out what the output DC no-load value would be -- it's related to the AC p-p input to the bridge, and to some number of diode drops. Picture what the bridge does when the AC waveform in is at it's positive peak value, and then at its negative peak value...
 
Last edited by a moderator:

Similar threads

  • · Replies 15 ·
Replies
15
Views
7K
  • · Replies 19 ·
Replies
19
Views
5K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
8K
  • · Replies 45 ·
2
Replies
45
Views
9K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
6K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 29 ·
Replies
29
Views
6K