Complex Integrals: Sketching Paths & Computing Integrals

Click For Summary

Homework Help Overview

The problem involves sketching paths in the complex plane and computing integrals of the real part of a complex function along those paths. The paths are defined as a: [0; 1] -> C, t -> t + it² and b: [0; 1 + i]. The integrals to be computed are ∫Re(z)dz over each path.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the sketching of path a and express uncertainty about path b's notation. There is a suggestion that path b may represent a line segment from 0 to (1+i), prompting questions about the definition of Re(z) in this context.

Discussion Status

Some participants have confirmed their understanding of path a, while others are seeking clarification on the notation used for path b. There is an ongoing exploration of the definitions and implications of the paths involved.

Contextual Notes

Participants note the distinction between the notations [0, 1] and [0; 1], indicating potential confusion over the representation of paths in the complex plane. There is also mention of the relationship between the two paths and their endpoints.

Maybe_Memorie
Messages
346
Reaction score
0

Homework Statement



Sketch the C1 paths a: [0; 1] -> C, t -> t + it2 and b: [0; 1 + i]. Then compute the following integrals.

∫Re(z)dz over a

∫Re(z)dz over b


Homework Equations





The Attempt at a Solution



Sketching a seems ok, y-axis is Imaginary, x-axis is Real, and the path is a quadratic between 0 and 1.

However I'm not sure about b...

As for the integrals, is it just a case of integrating Re(a(t))a'(t)dt between 0 and 1, then integrating Re(a(t))a'(t)dt between 0 and 1+i?
 
Physics news on Phys.org
Hi MM!

I believe you've got (a) down.

For (b) I have to admit I haven't seen the notation [0; 1 + i] before.
Do you have a definition for it?
I'd assume it's supposed to represent the line segment between 0 and (1+i).
Or in other words: (1+i)[0, 1].
It looks a bit weird though, since a curve is usually defined on an interval of real numbers.
However, if this is the case, you need to reconsider what Re(z) is.
 
I like Serena said:
Hi MM!

I believe you've got (a) down.

For (b) I have to admit I haven't seen the notation [0; 1 + i] before.
Do you have a definition for it?
I'd assume it's supposed to represent the line segment between 0 and (1+i).
Or in other words: (1+i)[0, 1].
It looks a bit weird though, since a curve is usually defined on an interval of real numbers.
However, if this is the case, you need to reconsider what Re(z) is.

I don't have a definition for it. I'll upload the actual problem to show it to you.
 

Attachments

Maybe_Memorie said:
I don't have a definition for it. I'll upload the actual problem to show it to you.

I get it, in particular if I look at the problems that are coming, that show which theory you're currently learning.

Path b is not related to path a.
It is just a (linear) path from 0 to (1+i).
It would be given by b:[0,1]→C defined by t→t(1+i)

Note that path a also starts in 0 and ends in (1+i).

And also note that for path a the interval is [0,1] and not [0;1].
[0,1] is a real interval, whereas [0;1] would indicate a (linear) path between 0 and 1 in the complex plane.
 

Similar threads

Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 105 ·
4
Replies
105
Views
11K
Replies
9
Views
2K
Replies
12
Views
2K
Replies
2
Views
2K
  • · Replies 26 ·
Replies
26
Views
5K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 7 ·
Replies
7
Views
2K