Complex Integration Along Given Path

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SUMMARY

The discussion centers on evaluating a complex integral along a specified path from z = 1 to z = 5 in the complex plane. The user attempts to apply Cauchy's Integral Formula with the function f(z) = 1 / (z + 4) but arrives at an incorrect result of I = 2 * pi * i instead of the expected value of 0.255. The confusion arises from the integration over a closed contour that includes z = 0 and the need to account for the additional path segment. The Residue Theorem is also referenced, confirming the discrepancy in results.

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  • Understanding of complex analysis concepts, specifically Cauchy's Integral Formula.
  • Familiarity with the Residue Theorem in complex integration.
  • Knowledge of parametrization techniques for complex paths.
  • Ability to evaluate integrals in the complex plane.
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usersusername1
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Homework Statement
I am asked to find the value of the integral I = dz / (z * (z + 4)) along the contour z = 4 * t * exp(-t * 2* pi * i) + 1, where the bounds of t are [0,1].
Relevant Equations
Cauchy's Integral Formula, Residue Theorem
From plotting the given path I know that the path is a curve that extends from z = 1 to z=5 on the complex plane. My plan was to parametrize the distance from z = 1 to 5 as z = x, and create a closed contour that encloses z=0, where I could use Cauchy's Integral Formula, with f(z) being 1 / (z + 4). This gives me an answer of I = 2 * pi * i, but I know the answer is supposed to be 0.255 (from evaluating the integral directly between z=1 and z=5. Using the Residue Theorem gives me the same answer, so I am unsure of how to proceed,
 
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I don't understand your plan. You can evaluate the integral on the closed contour, but so what? You have no idea what the integral is on the extra piece you added to the path.
 
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Office_Shredder said:
I don't understand your plan. You can evaluate the integral on the closed contour, but so what? You have no idea what the integral is on the extra piece you added to the path.
I was parametrizing that piece as z = x & dz=dx and evaluating the integral between 1 and 5. I guess I am stuck on how to actually incorporate the given path into an integral.
 
usersusername1 said:
From plotting the given path I know that the path is a curve that extends from z = 1 to z=5 on the complex plane. My plan was to parametrize the distance from z = 1 to 5 as z = x, and create a closed contour that encloses z=0, where I could use Cauchy's Integral Formula, with f(z) being 1 / (z + 4).
What happened to the ##1/z## factor? What is the residue of ##1/(z(z+4))## at ##z=0##?
usersusername1 said:
This gives me an answer of I = 2 * pi * i,
That is for the entire closed curve, right?
usersusername1 said:
but I know the answer is supposed to be 0.255 (from evaluating the integral directly between z=1 and z=5.
Is 0.255 for the part of the closed path that you added, or is it a book answer for the original partial path? I would be surprised if the final answer was not complex.
usersusername1 said:
Using the Residue Theorem gives me the same answer, so I am unsure of how to proceed,
I have not tried to follow the details, but I think that you now have ##2 \pi i = -DesiredIntegral + 0.255##. So now you can easily find the value of ##DesiredIntegral##. (I put the minus sign in because it looks like the original path is clockwise. "the bounds of t are [0,1]" is not clear. Is it from 0 to 1 or is it from 1 to 0?)
 
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