Complex number(exponential form)

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The discussion revolves around solving the equation e^w = Z, where Z is defined as 1 + √3. The user proposes a solution by converting Z into exponential form, resulting in w = i(π/3). Other participants confirm the validity of this approach by demonstrating that the exponential form accurately represents Z. Ultimately, the user receives affirmation that their solution is correct. The thread highlights the importance of verifying complex number solutions through exponential representation.
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Homework Statement



hey there.. I've try this question(below)..
but, i don't know whether my solution is correct or not..

Find a possible value for w that satisfies relation...
e^w = Z -->where z = 1 + 3^1/2


my solution...
r = 2
theta = pi/3
change z into exponential form...
z = 2e^i(pi/3)

hence, w = i(pi/3)

can anybody pleas guide me or verified my answer...
 
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You mean
R.e^w = Z -->where z = 1 + 3^1/2.j

If r = 2
and w = j (pi/3)

Knowing
R . e^(j.t) = R. [cos(t) + j sin(t)],

2 . e^(j. pi /3) = ... ?
 
rootX said:
2 . e^(j. pi /3) = ... ?

2 . e^(j. pi /3) = 2[cos (pi/3) + i sin (pi/3)]
 
naspek said:
2 . e^(j. pi /3) = 2[cos (pi/3) + i sin (pi/3)]

Which equals z, hence verifying that your solution is good.
 
ok.. so.. is my answer is correct?
 
rootX said:
...verifying that your solution is good.
naspek said:
ok.. so.. is my answer is correct?
What rootX said is another way of saying "yes, it is correct" :smile:
 
thanks guys! really appreciate your help.. =)
 

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