Proof of Complex Conjugates and Real Coefficients | Complex Numbers Homework

Click For Summary

Homework Help Overview

The discussion revolves around the proof involving complex numbers and their conjugates, specifically focusing on the condition that the product of two complex numbers results in a polynomial with real coefficients.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to establish a proof that if two complex numbers are conjugates, then the resulting polynomial has real coefficients. Participants suggest writing out the polynomial explicitly to check for complex components.

Discussion Status

Participants are exploring the implications of the condition stated by the original poster. Some guidance has been offered regarding the approach to take, but there is no explicit consensus on the next steps or resolution of the problem.

Contextual Notes

The original poster expresses a need to prove the converse of their initial statement, indicating a focus on the implications of the "if and only if" condition. There is a mention of the original poster's reluctance to engage further with the problem initially.

astrololo
Messages
200
Reaction score
3

Homework Statement



I have two complex numbers that are non real, k and z. K and z are going to be complex conjugates if and only if the product (x-k)(x-z) is a polynomial with real coefficients.

Here is my answer :

k=a+bi

z=c+di

(x-k)(x-z) = x^2 -(k+z)x+kz

Homework Equations

The Attempt at a Solution


I was able to prove that a=c and d=-b (I have proven they're conjugatCes)

But because this is a if and only if, I must prove that if they're conjugates, then the coefficients are real. How do I do that ?
 
Physics news on Phys.org
So k = a + bi and z = a - bi. Now write out (x-k)(x-z) and see if there's anything complex left over or not !
 
BvU said:
So k = a + bi and z = a - bi. Now write out (x-k)(x-z) and see if there's anything complex left over or not !
To be honest, I did think about doing that but I was lazy and didn't try it and went just to ask this question... Thank you !
 
Being lazy is often a good quality for finding an economic way out of a problem :smile:
 

Similar threads

  • · Replies 20 ·
Replies
20
Views
3K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
Replies
39
Views
6K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
Replies
9
Views
2K