Complex number problem with trig functions

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SUMMARY

The discussion focuses on finding the second derivative, d²/dx², and both complex number forms for the expression (1 + i cos(x)) / (1 - i cos(y)). Participants clarify that the expression is not an equation due to the absence of an equal sign. Key equations referenced include z = a + bi and the polar form re^(iθ). The conversation emphasizes the importance of expressing the function in terms of z and polar representations to simplify the differentiation process.

PREREQUISITES
  • Understanding of complex numbers, specifically the forms z = a + bi and re^(iθ).
  • Familiarity with trigonometric functions and identities.
  • Knowledge of calculus, particularly differentiation and second derivatives.
  • Basic algebraic manipulation skills for handling complex fractions.
NEXT STEPS
  • Learn how to differentiate complex functions using the chain rule.
  • Study the application of polar coordinates in complex analysis.
  • Explore the use of trigonometric identities in simplifying complex expressions.
  • Investigate the properties of complex derivatives and their geometric interpretations.
USEFUL FOR

Students studying complex analysis, mathematicians working with trigonometric functions, and anyone interested in advanced calculus involving complex numbers.

SlushmanIU
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Homework Statement


Find d^2/dx^2 and both complex number forms for the complex number equation (1+icos(x))/(1-icos(y))[/B]

Homework Equations


1. z=a+bi
2. re^itheta

The Attempt at a Solution


I have multiplied both sides by 1+icosy and gotten as far as (1+icosx+icosy-cosxcosy)/(1+cos^2y) but am going in circles after that. None of the trig identities seem to get me anywhere either.
 
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SlushmanIU said:

Homework Statement

[/b]
Find d^2/dx^2 and both complex number forms for the complex number equation (1+icos(x))/(1-icos(y))
That's an expression, not an equation. There's no equal sign.

Homework Equations


1. z=a+bi
2. re^itheta

The Attempt at a Solution


I have multiplied both sides by 1+icosy and gotten as far as (1+icosx+icosy-cosxcosy)/(1+cos^2y) but am going in circles after that. None of the trig identities seem to get me anywhere either.
Multiplied both sides of what? Which problem are you trying to solve first?
 
Is the problem asking you to express the ##\frac {d^2}{dx^2} ## in terms of z and polar representations?
Are you starting with ##g : \mathbb{R}^2 \to \mathbb{C} : g(x,y) = \frac{ 1 + i cos x }{1-i cos y}=z ##?
The second derivative should be straightforward.
If you are simply trying to get into a : z = a+bi : form, your first attempt is sufficient to break the fraction into real (a) and imaginary (b).
 

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