(adsbygoogle = window.adsbygoogle || []).push({}); 1. I have been asked to add 1/z1+1/z2+1/z3=Y. When z1=2+j2 and z2=1+j5 and z3=j6.

3. I have basically treated them like a normal resistors in parallel equation using 1+j0 and dividing them individually and then adding the product to get Y=0.29-j0.55. Is this the right way to go about this ?

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# Homework Help: Complex Numbers added as impedances in parallel

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