- #1
mohammed El-Kady
- 32
- 2
If we have y=x^2 -4. This is represented by curve intersect x-axis at (-2, 0) and (2, 0) or if we wish to find it algebraically we set y =0 then we solve it. The roots must lie on the curve.
when y=x^2+4 the roots are 2i and -2i "complex" consequently there is no intersection with x-axis, so where the points (2i, 0) and (-2i, 0) on the curve?
Does it have another dimension or imagine dim.? if yes, is that mean the curve is solid?
when y=x^2+4 the roots are 2i and -2i "complex" consequently there is no intersection with x-axis, so where the points (2i, 0) and (-2i, 0) on the curve?
Does it have another dimension or imagine dim.? if yes, is that mean the curve is solid?