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Complimentary Angles

  • Thread starter Miike012
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  • #1
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Homework Statement


It bascially says when the sum of two angles are 90 deg they are complimentary....
Then it goes on saying
sin(90-theta) = cos theta
and so on.....

I understand the concept such as if sin(30) = cos(60)
But the book doesnt explain why it works.. it just says if two compl angles are 90 deg then sin(90-theta) = cos theta, which is not an explanation at all...
can some one help me understand why this is?

Thank you.



Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
eumyang
Homework Helper
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I understand the concept such as if sin(30) = cos(60)
First of all, you forgot the degree marks. If you write "sin(30) = cos(60)", I'm assuming you meant radian measure. You must write sin (30°) = cos (60°). Secondly, If you "understood" the concept above, then why are you asking it in the first place? Sounds like you really don't understand.

Look at this diagram:
[PLAIN]http://home.comcast.net/~yeongil/images/RtTri.jpg [Broken]
In a right triangle, the two non right-angles have to be complements of each other.
[tex]\sin B = \frac{opp}{hyp} = \frac{b}{c}[/tex]
and
[tex]\cos A = \frac{adj}{hyp} = \frac{b}{c}[/tex]
so
[tex]\sin B = \cos A[/tex].
Since B = 90° - A,
[tex]\sin (90^{\circ} - A) = \cos A[/tex].
 
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