Compound Interest: Grow $1000 to $1500 in 5 Years?

AI Thread Summary
To determine the interest rate needed for an investment of $1000 to grow to $1500 in five years with quarterly compounding, the equation 1500 = 1000(1+x/4)^(20) is set up. After simplifying, the solution involves taking the 20th root and applying logarithms, leading to the calculation of x, which results in an interest rate of approximately 8.2%. The discussion highlights the confusion around logarithmic methods and emphasizes that there are multiple approaches to solving such problems. Participants note that while logarithms are useful, simpler methods like taking roots can also be effective. Overall, understanding various techniques for calculating compound interest is beneficial for tackling similar financial problems.
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At what rate of interest compounded quarterly, to the nearest tenth of a percent, will an investment of $1000 grow to $1500 in 5 years?

I set the problem up 1500=1000(1+x/4)^(4*5)

I then divided by 1000

1.5 = (1+x/4)^20

But this is where I'm stuck.
 
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Well, that's a twentieth degree polynomial.

Just take the 20th root of both sides.
 
Use a logarithm. Get a numerical answer for log(1+x/4). Then exponentiate.
 
Thanks for the replies, I ended up trying that & got

ln 1.5 = 20 ln (1+x/4)

ln1.5/20 = ln (1+x/4)

1+x/4 = e^.02027

x/4 = .02048

x = .08191 or 8.2%

What kept throwing me off was I kept getting the wrong answer because I kept dividing by four. After doing so many of these problems in a row, thought I was getting confused w/what could be done & couldn't be done regarding logarithms. Thanks again for the help.
 
^{20}\sqrt{1.5}=1+x/4 \mbox{ so that } 4^{20}\sqrt{1.5}-4=x

In fact, that's how you can set up a general formula for nominal interest rates.
 
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ZioX said:
^{20}\sqrt{1.5}=1+x/4 \mbox{ so that } 4^{20}\sqrt{1.5}-4=x

Yes, it's the same thing.
 
Only because you went around and made exp(.02027)=1.5^(1/20) which was an unnecessary step.

I'm not being adversarial, but the OP should know that there are more tools to use.
 
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Thats pretty interesting, I'm in the logarithm section in pre-calc, so that's why they were used. Good to know that there are other ways to solve the problem as well.
 
ZioX said:
Only because you went around and made exp(.02027)=1.5^(1/20) which was an unnecessary step.

I'm not being adversarial, but the OP should know that there are more tools to use.

I'm not disagreeing. The method using logarithms simply dates from an age when taking a twentieth root wasn't an easy thing. The logs are one way to accomplish that (by turning the root into division).
 
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I just took an actuarial course a couple of semesters ago, and they were able to generate a general formula for variable compounding periods. It utilized mth roots, hence my bias towards them.
 
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