Compound microscope focal length

AI Thread Summary
The discussion focuses on calculating the focal length of the objective lens in a compound microscope setup. Given the barrel length of 15 cm, the specimen distance of 1 cm from the objective, and the eyepiece focal length of 5 cm, the relationship between the distances and focal lengths is explored. The equations used include the lens formula and the relationship between the distances of the intermediate image and the eyepiece. It is suggested that the intermediate image should be formed at the eyepiece's focal point to ensure optimal viewing for the human eye. This understanding is crucial for solving the problem effectively.
Cataklyzm
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Homework Statement


The barrel of a compound microscope is 15 cm in length (distance between lenses). The specimen will be mounted 1.0
cm from the objective, and the eyepiece has a 5.0-cm focal length. Determine the focal length
of the objective lens.
Known: f2=5cm, L=15cm, do1=1cm
Unknown: f1, di1, di2, do2

Homework Equations


1/di+1/do=1/f


The Attempt at a Solution


A. I drew a diagram: I believe di1+do2=L
B. I have the equations:
1/di1+1=f/f1
1/di2+1/do2=1/5
di1+do2=15

I think there is some relation to distances that I'm not seeing.
 
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Must the intermediate image be formed at the focal point of the eyepiece? I think that could solve my distance dilemma.
 
Cataklyzm said:
Must the intermediate image be formed at the focal point of the eyepiece? I think that could solve my distance dilemma.

Yes, and you should be able to explain why (hint: the normal human eye likes plane waves!).
 

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