Compute Impact Velocity Vector for Orbital Trajectory

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A craft in orbit at a height above a planet experiences a force acting against its motion, leading to deceleration and eventual impact. To compute the velocity vector upon impact, methods vary based on the force's characteristics; for short-duration forces, position and velocity can be calculated to derive a new Kepler orbit, while longer forces may require numerical simulations. For small forces akin to air drag in a nearly circular orbit, a simulation yielded an impact speed of 0.3116 m/s for a cubesat starting from a 50km orbit. The discussion highlights the challenges of air drag at low altitudes and questions the feasibility of simulating such forces in a vacuum environment like the moon. Overall, understanding these dynamics is crucial for accurate trajectory predictions in orbital mechanics.
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Let's say a craft is in an orbit at a height h above a planet or moon. A force acts directly against the craft's direction of motion so as the force vector is always parallel to the surface of the central body. So, the craft will slowly decelerate and impact the surface. What would be the best way to compute the velocity vector upon impact? I don't have much experience at all with orbital trajectories, and it seems like an interesting question with simple parameters.
 
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If the force acts for a short time: Calculate the position+velocity afterwards, derive parameters of a new Kepler orbit, evaluate this at the radius of the planet/moon.
If the force is significant and acts in a complicated way for a longer time: Numerical simulation?
If the force is like air drag and small everywhere and the initial orbit is roughly circular: Assume a nearly circular orbit at impact, calculate the corresponding speed.
 
I wanted a more exact result for that third option, and I couldn't derive a formula, so I did a simulation. It was actually much easier than I thought it was going to be, pretty cool as well. I got an impact speed of .3116 m/s in the straight down direction. Craft mass = 1.3kg (cubesat), F = .0001 N in the direction opposite of velocity, starting from 50km orbit. Very strange to thing about an object coming in for landing this way, nearly in orbit extremely close to the surface.
 
In 50km, there is nothing which I would call orbit, there is too much air drag.
 
mfb said:
In 50km, there is nothing which I would call orbit, there is too much air drag.
The moon is a vacuum for all practical purposes, especially at 50km altitude.
 
But how do you get air drag there? Or do you provide that force via thrusters?
 
I built a device designed to brake angular velocity which seems to work based on below, i used a flexible shaft that could bow up and down so i could visually see what was happening for the prototypes. If you spin two wheels in opposite directions each with a magnitude of angular momentum L on a rigid shaft (equal magnitude opposite directions), then rotate the shaft at 90 degrees to the momentum vectors at constant angular velocity omega, then the resulting torques oppose each other...

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