Concept : Capacitors in Parallel

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SUMMARY

The discussion centers on the concept of equivalent capacitance in parallel configurations of capacitors. When capacitors of equal value are connected in parallel, the total capacitance increases because the effective plate area doubles, leading to a higher charge storage capacity. The formula for capacitance, C = εA/d, illustrates that with two capacitors, the effective area (A) increases, resulting in an equivalent capacitance that is the sum of the individual capacitances. Thus, two capacitors rated at 10 Coulombs per Volt in parallel yield an equivalent capacitance of 20 Coulombs per Volt.

PREREQUISITES
  • Understanding of basic capacitor theory
  • Familiarity with the formula for capacitance: C = εA/d
  • Knowledge of charge-voltage relationships in capacitors
  • Concept of parallel versus series capacitor configurations
NEXT STEPS
  • Study the effects of dielectric materials on capacitance
  • Learn about the implications of capacitor configurations in circuit design
  • Explore the concept of energy stored in capacitors
  • Investigate real-world applications of capacitors in parallel circuits
USEFUL FOR

Electrical engineers, physics students, and anyone interested in understanding capacitor behavior in parallel configurations will benefit from this discussion.

thebiggerbang
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What is the conceptual perspective of why equivalent capacitance is in parallel is more than the individual capacitance?
(assume we have a parallel network of capacitors of equal value)

I know the formulae, decoded the concept behind the eq cap in series but couldn't make any sense out of the parallel combo!
 
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thebiggerbang said:
What is the conceptual perspective of why equivalent capacitance is in parallel is more than the individual capacitance?
(assume we have a parallel network of capacitors of equal value)

I know the formulae, decoded the concept behind the eq cap in series but couldn't make any sense out of the parallel combo!

Are you familiar with the equation that is used to calculate the capacitance of a simple parallel plate capacitor?

[tex]C = \frac{\epsilon A} {d}[/tex]

Where A is the plate area and d is the plate separation. What can you say about the effective area of two caps in parallel? What does that do to the capacitance C in that equation? :smile:
 
Capacitance is C = q/V .
I say, Capacitance of the capacitor in my hand is 10 Columb per Volt. Which means, If I put in 10 Columbs of charge into it I will get a voltage rise of 1 Volt.
So, If I have two such capacitors in parallel, I would have to put 20 Columb to get a voltage rise of 1 Volt.
So, two 10 columb per volt capacitor in parallel is 20 columb per volt capacitor (because, they have to share the charges (unlike series configuration))
 

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