I was reading a solution to the following question:
Given v(t) = 22 + 18 t, use calculus to determine the total displacement from t initial= 1.5 s to t final = 3.1 s
Here are the steps in the equation:
I get everything up to the last part, where we take get (3.1^2 - 1.5^2)... Why is that we don't do (3.1-1.5)^2 instead? I had always imagined the it would be [tex]\Delta[/tex]t squared, so just final minus initlal, then squaring the result, and not the final time squared minus initial time squared.
Would be great if you guys could clear up my confusion.
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