Conceptual? question of direction/magnetic force of current in x-y plane

AI Thread Summary
The discussion centers on determining the direction of the magnetic force on an electron located at the origin, influenced by three long wires carrying current out of the x-y plane. Participants clarify that the magnetic field generated by the wires can be calculated using the formula B = μ0I/(2πr) and the right-hand rule to establish the direction of the magnetic field. The Lorentz force equation is emphasized for calculating the magnetic force on the electron, with the conclusion that the force is directed out of the page, towards the positive z-axis. Misunderstandings regarding the nature of charge in the wires and the distinction between electric and magnetic fields are addressed. Ultimately, the correct interpretation of the magnetic force direction is confirmed to be out of the page, not towards the negative x-axis.
rfig08d
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Homework Statement


3 long wires are perpendicular
efqiow.jpg
Each passes through x-y plane with a distance of L from origin. Each wire has a current, I, directed out of the drawing's plane. An electron is located a the origin with a velocity along the positive x-axis. What is the direction of the magnetic force on the electron?


Homework Equations


From what I know F = (4pix10^-7)I/(2*pi*r)


The Attempt at a Solution


I'm at a loss for this... but my thoughts on this are: Would each current (I1, I2, I3) have a negative charge and repel the electron out of the plane towards the negative x-axis?

The answer states that it is "out of the page (ie: graph)" and my understanding makes sense, correct?
 
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rfig08d said:
From what I know F = (4pix10^-7)I/(2*pi*r)
Nooo, that's the magnetic field strength, not the force! :smile:

For a straight, long wire (not within in a magnetic material),
B = μ0I/(2πr)​
Use the right-hand rule to find the direction of the vector B.

Then use the Lorenz force equation (with E = 0) to find the force (which also might involve using the right-hand-rule).

The Attempt at a Solution


I'm at a loss for this... but my thoughts on this are: Would each current (I1, I2, I3) have a negative charge and repel the electron out of the plane towards the negative x-axis?
No, there is no net charge on the wire*. For every negative electron in the wire, there is also a positive proton in the wire. The net charge, and thus net electric field, is zero. For this problem you need to deal with magnetic fields, not electric fields.

*I'm intentionally leaving concepts of special relativity out of this conversation. they're not necessary to solve this problem
The answer states that it is "out of the page (ie: graph)"
Yes, out of the page is correct (not toward the negative x-axis). Out of the page meaning toward the positive z-axis.
 
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