Conducting rail ciruit, against gravity

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SUMMARY

The discussion focuses on calculating the current (I) required to counteract gravitational force (Fg) in a vertically oriented conducting rail system. The relevant equations include Fg = mg, where m is the mass of the rod, and the magnetic force equation F = IlB, where I is the current, l is the length of the conductor, and B is the magnetic field strength. The user seeks to establish a relationship between the magnetic field and gravitational force to ensure the system does not accelerate beyond a specified velocity. The derived formula for magnetic levitation is confirmed as Fg = IlB, allowing for the determination of the necessary current.

PREREQUISITES
  • Understanding of electromagnetic principles, specifically Lorentz force.
  • Familiarity with the equations of motion and gravitational force.
  • Knowledge of circuit theory, particularly Ohm's Law (R = ΔV/I).
  • Basic concepts of magnetic fields and their interactions with electric currents.
NEXT STEPS
  • Study the derivation of the magnetic levitation formula F = IlB.
  • Explore the principles of electromagnetic induction and its applications.
  • Learn about the design and analysis of vertical rail systems in physics.
  • Investigate advanced topics in electromagnetism, such as Maxwell's equations.
USEFUL FOR

Students and educators in physics, electrical engineers, and anyone interested in the principles of electromagnetic systems and their applications in vertical motion scenarios.

Frostfire
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Homework Statement



So my textbook has a lot of example of conducting rails moving horizontally with unknown variables of F and B, but how would you approach a problem that has such a device pointed vertically with the moving bar droping? let's say R and B are known and we need to find I(current) sufficient to counteract gravity so it doesn't accelerate past a velocity required to generate that current.

Homework Equations


Fb=qv x B
R = delta V/I
Fg = mg (call the mass of the rod m )
I = p/delta V


The Attempt at a Solution



I played with it, but not sure if I am right.The part I am stuck on is what relation of the magnetic field do I set equal to Fg

is it Fg= qV x B
 
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So I found a formula for magnetic levitation that allows me to relate magnetic field strength and gravity

F= IlB=mg

if I am right this allows me to determine the current needed to counteract gravity.Does this sound right? Anybody no where that formula is derived from?
 
Can somebody give me some advice here? Its kind of hard to ask questions that aren't in the book, if your unsure of what your doing :rolleyes:
 

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