Not sure where I made the mistake? 1. for f(x)=[2x-4]/[x^2-x-2], which of the following is true? I. f(x) has no relative extrema II. There are vertical asymptotes at x=2 and x=-1 III. There is a horizontal asymptote at y=0 My answer: Only II & III cuz i dont get how one is right? what I did was: f'=[2x^2+8x-8]/[x^2-x-2]^2 is that the right answer for the derivative? cuz if it is, wouldnt u be able to find x by setting the top part = to 0?