Confused know how to do it one way but not the other.

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SUMMARY

The discussion centers on calculating the speed of a hawk's shadow on the ground when diving at a velocity of 5.00 m/s at an angle of 60.0 degrees below the horizontal. The initial calculation using the sine function yielded a horizontal shadow speed of 2.5 m/s. Participants clarified that the correct approach involves using the cosine function to find the horizontal component of the velocity, specifically Cos(60°), which equals 0.5. This leads to the conclusion that the shadow's speed is actually 2.5 m/s, confirming the initial calculation was correct.

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Homework Statement



when the sun is directly overhead, a hawk dives towards the ground with a constant velocity of 5.00m/s at 60.0 degrees below the horizontal. calculate the speed of its shadow on the level ground.


Homework Equations



sin rule



The Attempt at a Solution



so far i got the ansewr by using 5sin(60) = 2.5m/s

but there is another way to do this by using the sin rule and i wanted to know how to do it that way too. for the sin rule the solution manual (put sin(90)/(5m/s)) = sin(30)/(Xm/s) i am confused why they use sin(90)/(5m/s) as a ratio with sin(30)/ (Xm/s). why can sin(90)/(5m/s) work as a ratio?
 
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I don't think you got the right answer if you used Sin60°.

60° with the horizontal suggests that the horizontal component of velocity is Cos60° which is the component parallel with the ground.

Cos60° = Sin30° which may be adding to your confusion.
 

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