Find magnitude and direction of F of a charge moving through a magnetic field.
velocity: 5 m/s
charge: 2 C
B: 3 T (pointing out of the page when drawn)
(vector)F=qv x B
The Attempt at a Solution
I know to use the equation for magnitude but I'm confused as to what the angle would be between v and B. Since the magnetic field is pointing out of the page, would the angle be 90°, making sin(90)=1?
Also, don't know what direction that would be. Since I don't know the direction of B, I'm not sure how to use the right hand rule to figure this out.