Confused on determining an enclosed a postive/negative/no net charge

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SUMMARY

The discussion centers on determining the net charge enclosed by a Gaussian cube in an electric field based on the flux through its surfaces. The user initially misinterprets the flux values, believing that the net charge for Cube 3 is negative due to an arithmetic error. The correct interpretations are: Cube 1 has no net charge, Cube 2 has a positive net charge, and Cube 3 has a negative net charge. The key takeaway is that the net flux through the surface determines the net charge, with positive flux indicating a positive charge, negative flux indicating a negative charge, and zero flux indicating no net charge.

PREREQUISITES
  • Understanding of Gaussian surfaces in electrostatics
  • Knowledge of electric flux and its relation to charge
  • Basic arithmetic skills for calculating net flux
  • Familiarity with the concept of electric fields and field lines
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  • Study the concept of electric flux in detail, focusing on Gauss's Law
  • Learn how to visualize electric field lines and their implications for charge distribution
  • Practice problems involving Gaussian surfaces and net charge calculations
  • Explore advanced topics in electrostatics, such as electric field strength and potential
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Students of physics, educators teaching electrostatics, and anyone interested in mastering the concepts of electric fields and charge interactions.

mr_coffee
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Hello everyone, I'm stuck on a check point. The figure shows three situations in which a Gaussian cube sits in an electric field. The arrows and hte values indicate the directions of th field lines and the magnitudes of the flux through the six sides of each cube. (The ligther arrrows are for the hidden faces.) In which situation does the cube enclose (a) a positive net charge,l (b) a negative net charge, and (c) no net charge. The image attached is the diagram from the book. I understood the concept when i read it. It said, If the electric field is outward for all points on its surface, the flux of the electric field is + and so is the enclosed charge. It also said, if the elelctric field is inward then the flux is - and so is the enclosed charge. If the positive and negative charges have equal magnitudes (there are as many field lines leaving surface as entering it) then there is no net charge or flux. The answer is, cube 1, no net charge. (2) positive net charge. (3) negative net charge. To start off, why is C no net charge? Maybe I don't know how to interpret the magnitudes. I see 4 going in and 7 going out, meaning +2 flux. 3 in, 2 out = -1 flux. 7 in, 5 out = -2. If i add up all these results i get -1 flux, wouldn't this mean it would be a overal net charge of negative? Am i totally not reading these right? :bugeye: I had to touch up the picture because you couldn't see the arrows or magnitudes after i scanned it, sorry about the sloppiness, paint sucks! Okay i just viewed the image and it sucks even more then I realized. So I'm going to list the magnitudes going in and out just to make sure.

Cube 2: Magnitude of arrows going into cube: 4, 3, 6; Going out of cube: 10, 3, 5.

Cube 3: In: 6,5,7; Out: 8,2,5
 

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mr_coffee said:
To start off, why is C no net charge? Maybe I don't know how to interpret the magnitudes. I see 4 going in and 7 going out, meaning +2 flux. 3 in, 2 out = -1 flux. 7 in, 5 out = -2. If i add up all these results i get -1 flux, wouldn't this mean it would be a overal net charge of negative?
You made an arithmetic error. The net flux is 0.
 
ahhh, my bad, thanks! I get it now! :biggrin:
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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