Confusion about Dielectrics and Potential Difference in Capacitors

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Inserting a dielectric between the plates of a capacitor reduces the potential difference (V) while keeping the charge (Q) constant, which leads to an increase in capacitance (C). The equation C=Q/V indicates that as V decreases, C increases. This can create confusion, as the textbook suggests that adding a dielectric increases the potential difference, which contradicts the established physics principles. The consensus is that the textbook may contain a misprint regarding the effect of dielectrics on potential difference. Understanding this relationship clarifies the behavior of capacitors with dielectrics.
KayleighK
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I'm reading my physics textbook right now and it states that when you add a dielectric between two capacitors you are:
1. Increasing the potential difference between the two plates.
2. Increasing capacitance by decreasing V (Q/V=C)

Isn't this contradictory? I thought that V in the equation (Q/V=C) was the potential difference between the capacitor plates. Therefore, if you decrease V, you woul be lowering the potential difference between the plates, not increasing it. Can someone explain this to me? Thank you.
 
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It is contradictory.
The effect of inserting a dielectric material between the plates of a charged capacitor, is to reduce the pd between those plates. (Charge stays constant)
This has the effect of increasing the capacitance.
C=Q/V so if you decrease V you increase C.
It must be a misprint.
 
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