- #1

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Text said:Consider a closed system containing 5 components A, B , C, D and E. We will assume tha E is inert and thus does not appear in the rxn:

[itex]v_AA +v_BB \leftrightharpoons v_CC + v_DD \qquad(1)[/itex]

where thev's are the stoichiometric coefficients. Note that the stoichiometric coefficients [itex]v_A, v_B, v_C, v_D[/itex] do not correspond to the respective number of moles present. The amounts of components are designated [itex]n_A,n_B,n_C,n_D[/itex]. However the, changes in the amounts of components present do bear a relationship to the values of the stoichiometric coefficients. That is,

[tex]

-\frac{dn_A}{v_A}=-\frac{dn_B}{v_B}=\frac{dn_C}{v_C}=\frac{dn_D}{v_D}\qquad(2)

[/tex]

I am a little confused as to the distinction between the

*n*'s and the

*v*'s. Is it saying that the

*n*'s are the

*actual amounts*present whereas the

*v*'s are the theoretical

*amounts needed for a balanced reaction*?

Thanks!

~Casey