Confusion with rope tension and monkeys

[ja!mee]

So I am again stuck on a question I have been provided. The question is:

Draw a FBD for each monkey. For each monkey, determine the rope tension that would allow the monkey to begin accelerating in the expected direction. (on a side note this is a pulley situation one monkey is 22kg and the other was 20kg and they are looking for both the maximum and minimum tension required)

So what I did is:

F_g22 – T= ma
T = F_g22 – ma
T = (22kg)(9.8 m/s) – (22kg)(0.47 m/s) = 205.26 N

Which I realize is the rope tension for the whole system. What I am confused on is... I thought that the tension in the rope would be the same throughout... am I missing a step? What I am thinking is what I have done is found the minimum tension only.

 

[technician]

I get the same answer as you and you are correct there is only one tension in the string... it is the same everywhere ... unless the pulley has a mass.