Confusion with rope tension and monkeys

  • Thread starter ja!mee
  • Start date
  • #1
16
0
So I am again stuck on a question I have been provided. The question is:

Draw a FBD for each monkey. For each monkey, determine the rope tension that would allow the monkey to begin accelerating in the expected direction. (on a side note this is a pulley situation one monkey is 22kg and the other was 20kg and they are looking for both the maximum and minimum tension required)

So what I did is:

Fg22 – T= ma
T = Fg22 – ma
T = (22kg)(9.8 m/s) – (22kg)(0.47 m/s) = 205.26 N

Which I realize is the rope tension for the whole system. What I am confused on is.... I thought that the tension in the rope would be the same throughout.... am I missing a step? What I am thinking is what I have done is found the minimum tension only.
 

Answers and Replies

  • #2
1,506
18
I get the same answer as you and you are correct there is only one tension in the string.... it is the same everywhere .... unless the pulley has a mass.
 

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