Confusion with the Gordon identity

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SUMMARY

The discussion centers on the Gordon identity in quantum field theory, specifically the expression involving the four-momentum vectors \( (p' + p)^{\mu} \). Participants clarify that the index \( \mu \) can only take values from 0 to 3, corresponding to the four components of a four-vector. Plugging in \( \mu = 5 \) is incorrect as it does not represent a valid component of a four-vector. Additionally, the distinction between \( \gamma^{\mu} \) and \( \gamma^{5} \) is emphasized, as they are fundamentally different entities.

PREREQUISITES
  • Understanding of four-vectors in quantum field theory
  • Familiarity with the Gordon identity and its applications
  • Knowledge of gamma matrices and their indices
  • Basic principles of quantum mechanics and relativistic physics
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  • Study the properties of four-vectors in quantum field theory
  • Learn about the implications of the Gordon identity in particle physics
  • Explore the role of gamma matrices, particularly \( \gamma^{5} \), in quantum field theory
  • Investigate common misconceptions regarding indices in tensor notation
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This discussion is beneficial for physicists, particularly those specializing in quantum field theory, students learning about particle physics, and anyone seeking to clarify the use of indices in tensor notation.

Higgsy
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For the Gordon identity

$$2m \bar{u}_{s'}(\textbf{p}')\gamma^{\mu}u_{s}(\textbf{p}) = \bar{u}_{s'}(\textbf{p}')[(p'+p)^{\mu} -2iS^{\mu\nu} (p'-p)_{\nu}]u_{s}(\textbf{p}) $$

If I plug in $\mu$=5, what exactly does the corresponding $(p'+p)^{5}$ represent?
4 vectors can only have 4 components so is this just an exponential?

Thanks
 
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That does not make sense. Why would you plug in ##\mu = 5##, and what would that be supposed to mean?
 
It is a 4vector...
( p' + p ) ^\mu = p'^\mu + p^\mu...
the first notation is shorter... :smile:

\mu is an index taking values 0,1,2,3...

Don't get confused with the \gamma^5... it is not \gamma^\mu with \mu=5, but it's a different object...
 
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