Confussion with setting up loading conditions on cylinder

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The discussion centers on setting up loading conditions for a horizontally supported cylindrical tube fixed at both ends in Abaqus. The user is confused about applying gravitational loads, questioning whether the load should be uniformly distributed across the tube's volume. It is clarified that gravity acts downward, and the user is advised to consider the direction of gravity in relation to cylindrical coordinates. The user confirms they are using a 3D model rather than cylindrical coordinates to avoid transformation complications. The gravitational force per unit volume is noted to be equal to the product of density and gravitational acceleration.
roldy
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I have a horizontally supported cylindrical tube that is fixed at both ends. I modeled half of it to run the simulation on in Abaqus. The only load that it has is its weight. What I get confused at with cylindrical geometry is applying the load. How should I apply the gravitational load and at what location?
 
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Isn't the gravitational load uniformly distributed over the volume of material comprising the tube?

Chet
 
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That is correct. I just wasn't sure how to set up the loading conditions on a cylindrical surface for gravity.
 
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roldy said:
That is correct. I just wasn't sure how to set up the loading conditions on a cylindrical surface for gravity.
The cylinder is horizontal and you are using cylindrical coordinates, correct? So the z axis of the cylindrical coordinate system is horizontal. But, gravity is acting downward. Can you represent the direction of gravity in terms of the circumferential coordinate θ and the cylindrical coordinate unit vectors?

Are you using a shell model or a 3D model? Or, are you treating the tube like a beam?

Chet
 
I am not using cylindrical coordinates, I don't want to have to do any coordinate transformations afterwards. I am using a 3D model that I created.
 
roldy said:
I am not using cylindrical coordinates, I don't want to have to do any coordinate transformations afterwards. I am using a 3D model that I created.
The (distributed) gravitational force per unit volume is equal to ρg, where ρ is the density.
 
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