Conical Pendulum: Mass, Speed, Frequency & Trajectory Explained

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SUMMARY

The discussion focuses on the analysis of a conical pendulum, where a ball attached to a string of length L swings in a horizontal circle at an angle (theta) with the vertical. Key equations derived include the mass of the ball as m = (Tcos(theta))/g, the speed of the ball as v = √(gLtan(theta)sin(theta)), and the frequency of revolutions as f = √(gLtan(theta)sin(theta))/(2πLsin(theta)). Additionally, it clarifies that when the string breaks, the ball moves tangent to the circular path initially but will follow a projectile trajectory until it hits the ground.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with circular motion concepts
  • Knowledge of trigonometric functions and their applications
  • Basic principles of projectile motion
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  • Study the derivation of centripetal force in circular motion
  • Learn about the dynamics of pendulums and their applications
  • Explore projectile motion equations and their implications
  • Investigate the effects of tension in strings on motion
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for clear explanations of conical pendulum dynamics and related concepts.

crhscoog
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Conical Pendulum--- did I do this right?

Homework Statement


A ball is attached to a string with length of L. It swings in a horizontal circle, with a constant speed. The string makes an angle (theta) with the vertical, and T is the magnitude of the tension in the string.

1)Determine the Mass of the Ball.
2)Determine the Speed of the Ball.
3)Determine the Frequency of revolutions of the Ball.
4)Suppose that the string breaks as the ball swings in its circular path. Qualitatively describe the trajectory of the ball after the string breaks but before it hits the ground.

The Attempt at a Solution



1)
F=Tsin(theta)=mg
m= (Tcos theta)/g

2)
Tcos(theta) = mg
T= mg/[cos(theta)]

F=Tsin(theta)=MAc
T=sin(theta)=(mv^2)/r

F= mg/[cos(theta)] * sin(theta) subtitute for T
F=mgtan(theta)

r=Lsin(theta)
F=(mv^2) / Lsin(theta)
mgtan(theta)=(mv^2)/ Lsin(theta)
v= square root of gLtan(theta)sin(theta)


3)
f= 1/t
t= x/v = 2(pi)r/v = 2(pi)Lsin(theta) / square root of gLtan(theta)sin(theta)

f= square root of gLtan(theta)sin(theta) / 2(pi)Lsin(theta)

4) What else can I say besides that it goes out in a straight line tangent to the "circle"?
 
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Hi crhscoog,

For #4, the ball does not move in a straight line. At the instant the string breaks, it is moving tangent to the circle, but what happens after that? From the way the questions is worded, I believe they want you to describe the motion up until the ball hits the ground.
 

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