Conical Tank Water Drainage: Finding Time to Empty with Differential Equations

  • Thread starter Thread starter chae
  • Start date Start date
  • Tags Tags
    Conical Tank
chae
Messages
1
Reaction score
0

Homework Statement


Water drains out of an inverted conical tank at a rate proportional to the depth (y) of water in the tank. Write a diff EQ as a function of time.

This tank's water level has dropped from 16 feet deep to 9 feet deep in one hour. How long will it take before the tank is empty.

Homework Equations



V=1/3pir2y

dV/dt=pi(r0/y0)2y2dy/dt

The Attempt at a Solution


The solution to the first question is: dy/dt=-k(y0/r0)2(1/piy)

I don't really know how to go about finding the time it will take to empty the tank.

Please help!
 
Last edited:
Physics news on Phys.org
hey, welcome to physicsforums! your solution to the first question is correct. (I'm guessing you're using 'k' as a constant. this is good.) So now, you need to make use of this differential equation to get 'y' as a function of time. You have hopefully done this kind of integral before. It just needs a bit of rearranging to get a nice answer.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top