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Could anyone help to show that if n is odd then the set of all n-cycles consists of two conjugacy classes of equal size in A_n? Thx
An n-cycle is a permutation of n elements in a specific order. In the context of this concept, it refers to a cycle of n elements in a symmetric group, where each element is mapped to the next element in the cycle.
In group theory, conjugacy refers to the relationship between two elements in a group, where one element can be transformed into the other by a group operation. For example, in a symmetric group, two n-cycles are conjugate if they have the same cycle structure.
This means that all odd n-cycles in a symmetric group are conjugate to each other. In other words, they can all be transformed into one another by a group operation.
The alternating group A_n is a subgroup of the symmetric group, consisting of even permutations. In this concept, we are specifically looking at odd n-cycles in the symmetric group, which are not in the alternating group. However, the conjugacy classes of odd n-cycles are the same in both groups.
Sure, let's consider the symmetric group S_4. There are two conjugacy classes of odd 3-cycles: (123) and (132). These two cycles are conjugate to each other, meaning they can be transformed into one another by a group operation. However, they are not conjugate to any even permutations, which are in the alternating group A_4.