- #1
ognik
- 643
- 2
Just checking (while trying to prove the Schwarz inequality for $<f|H|g>$, I know $ <f|g>=<g|f>^* $ please confirm/correct :
If $ \psi=f+\lambda g, \:then\: \psi^*=f^*+\lambda^* g^* $
Is $ <f^*|g>=<g^*|f>^* $ and $ <f^*|H|g>=<g^*|H|f>^* $ (H hermitian)?
Is $ <f^*|H|g><g^*|H|f> = - <g^*|H|f><f^*|H|g> $
Thanks
If $ \psi=f+\lambda g, \:then\: \psi^*=f^*+\lambda^* g^* $
Is $ <f^*|g>=<g^*|f>^* $ and $ <f^*|H|g>=<g^*|H|f>^* $ (H hermitian)?
Is $ <f^*|H|g><g^*|H|f> = - <g^*|H|f><f^*|H|g> $
Thanks