Conservation of (Angular) Momentum

AI Thread Summary
The discussion centers on a physics problem involving a wooden block sliding up a rough incline, where the goal is to determine the maximum height reached in terms of a previously calculated height (H = vi^2/2g). The user applies conservation of energy, equating kinetic energy at the bottom to potential energy at the top plus work done against friction. The challenge arises in determining the distance (d) the block travels up the ramp, which is necessary for the final answer but cannot be included in the expression. The user also seeks clarification on whether to express the final answer in terms of the previously found height, H. Additionally, there is a mention of a similar problem involving a hoop, indicating a potential shift in focus.
velvetymoogle
Messages
24
Reaction score
0
Hi.
The problem is "A wooden block of mass m slides with an initial speed of vi up a straight incline that makes an angle of theta with the horizontal. If the incline is rough with a coefficient of kinetic friction uk, determine the maximum height it rises in terms of h found in part a (which was H = vi^2/2g)"

So what I did was conservation of energy. KE at the bottom = PE at the top + Work.
mgh + Fd = 1/2mv^2
h = [mvi^2 - ukmgcos(theta)d]/mg
pPoblem is, I don't know what d is and it can't be part of my final answer. I know it's the distance that the block travels up the ramp, but how do I figure that out.
Also, since it says in terms of h found in part a, does that mean I set everything equal to vi^2/2g?

How would I do this with a hoop with radius R?
 
Physics news on Phys.org
Sorry. Realize this is in the wrong spot.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top