Conservation of angular momentum

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SUMMARY

The discussion centers on the conservation of angular momentum in a system where a body is attached to a massless string and rotated without external tangential forces. The angular momentum is defined by the equation Lo = Ro * Vo * m, where Ro is the initial radius, Vo is the initial tangential velocity, and m is the mass. As the string is pulled, the velocity is expressed as V(t) = (Vo * Ro) / r(t), and the tangential acceleration is given by a(t) = (-Vo * Ro) / (r(t)^2) * r'(t). The conversation concludes that this acceleration can be combined with external forces affecting tangential acceleration, provided that external forces do not alter r'(t>.

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Imagine a body that is attached to a massless string and then rotated in such a manner that no external forces like gravity acts on the body in tangential direction.

The body now has the angular momentum with respect to the axis of rotation

Lo = Ro * Vo * m

Where

Ro = constant initial radius of rotation
Vo = constant initial tangential velocity
m= mass of the body

If the string is pulled in with respect to time, and no torque is applied with respect to the axis of rotation would the velocity be this, according to the law about conservation of angular momentum?

V(t)=[itex]\frac{Vo*Ro}{r(t)}[/itex] ?



And would the tangential acceleration then be

a(t)=[itex]\frac{-Vo*Ro}{(r(t)^2)}[/itex]*r(t)' ?

Where

r(t)´ = the derivate of the radius of rotation with respect to time

If so, could this acceleration be added directly to external forces that is causing tangential acceleration?

The purpose is forwarding a regulator that will control the acceleration of a robot.
 
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Looks right.
External forces could change r'(t), but if they do not, I would expect that you can add them.
 

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