How Does Charge Redistribution Affect Forces in a Triangular Sphere System?

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SUMMARY

The discussion focuses on calculating the electrostatic forces between three identical conducting spheres arranged in an equilateral triangle with a side length of 24.0 cm. The charges on the spheres are qA = -3.45 nC, qB = -3.91 nC, and qC = +6.09 nC. The initial calculation for the force between spheres A and C yielded a magnitude of 3.28 x 10^-6 N. Subsequent steps involve connecting spheres A and B, grounding B, and then connecting B and C to determine the new forces between the spheres after charge redistribution.

PREREQUISITES
  • Understanding of electrostatics and Coulomb's law
  • Familiarity with charge redistribution concepts
  • Knowledge of conducting spheres and their properties
  • Ability to perform calculations involving electrostatic forces
NEXT STEPS
  • Calculate the final charges on spheres B and C after they are connected
  • Learn about the implications of grounding in electrostatic systems
  • Explore the concept of electrostatic force calculations in multi-sphere systems
  • Review the principles of charge conservation in electrostatics
USEFUL FOR

Students studying electrostatics, physics educators, and anyone interested in understanding charge redistribution effects in conductive systems.

Shatzkinator
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Homework Statement



In the figure 21-40, three identical conducting spheres form an equilateral triangle of side length d = 24.0 cm. The sphere radii are much smaller than d and the sphere charges are qA = -3.45 nC, qB = -3.91 nC, and qC = +6.09 nC. (a) What is the magnitude of the electrostatic force between spheres A and C? The following steps are taken: A and B are connected by a thin wire and then disconnected; B is grounded by the wire, and the wire is then removed; B and C are connected by the wire and then disconnected. What now are the magnitudes of the electrostatic force (b) between spheres A and C and (c) between spheres B and C?
http://edugen.wiley.com/edugen/courses/crs1650/art/qb/qu/c21/fig21_41.gif



Homework Equations


F = kq1q2/r^2


The Attempt at a Solution



I got 3.28 x 10^-6 N for part A... not sure what to do for B and C
 
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Shatzkinator said:
... not sure what to do for B and C

Follow the subsequent steps. When A and B are connected what charge ends on each? Then B is rounded so the charge on B is now 0. Now B and C are connected and you end up with how much charge on B and C?

Now it looks like you're back to calculating forces again.
 

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