Conservation of Energy and satellite

AI Thread Summary
The discussion focuses on applying the conservation of energy and angular momentum principles to determine the initial speed of a satellite launched from a nonrotating planet. A user attempts to derive the equation but realizes their calculations are incorrect. Another participant advises using two equations derived from conservation laws to solve for the unknowns. The conversation emphasizes the importance of correctly applying these principles, especially noting that the satellite's speed is not zero at its maximum distance. The user plans to revisit the problem with this guidance in mind.
phy
Imagine a spherical, nonrotating planet of mass M, radius R, that has no atmosphere. A satellite is fired from the surface of the planet with speed vo at 30 degrees to the local vertical. In its subsequent orbit the satellite reaches a maximal distance of 5R/2 from the center of the planet. Using the principles of conservation of energy and angular momentum, show that vo - (5GM/4R)^1/2


This is what I've done so far and it's not right:

E=1/2 mv^2 - GMm/2R = GMm/4R
1/2mv^2-GMm/2(5R/2) = GMm/4(5R/2)
1/2mv^2-GMm/5R = 2GMm/20R
1/2v^2 = 3GM/10R
.:v = (3GM/5R)^1/2

Clearly, this isn't the answer I should be getting. Does anybody know where I'm going wrong?
 
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phy said:
E=1/2 mv^2 - GMm/2R = GMm/4R
1/2mv^2-GMm/2(5R/2) = GMm/4(5R/2)
1/2mv^2-GMm/5R = 2GMm/20R
1/2v^2 = 3GM/10R
.:v = (3GM/5R)^1/2
I can't quite follow what you are doing. Apply conservation of energy to get one equation and conservation of angular momentum to get another. (I trust you realize that at the maximal distance, the speed is not zero.)
 
So I'm just going to be solving a system of 2 linear equations for 2 unknowns?
 
phy said:
So I'm just going to be solving a system of 2 linear equations for 2 unknowns?
I wouldn't call them linear... but, yes, you'll have two equations and two unknowns.
 
Oh yeah my bad. I meant just two equations. Ok thanks for that. I guess I'll redo the question and get back to you on that one. Thanks again.
 
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