Conservation Of Mechanical Energy PROBLEM

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CoffinSupply
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Homework Statement



A novice skier, starting from rest, slides down a frictionless 35.00 incline whose vertical height is 185 m.How fast is she going when she reaches the bottom?


Homework Equations



Need the rest of the solution.

The Attempt at a Solution



PICTURE SCAN: http://img528.imageshack.us/img528/8666/homeworkgi6.jpg

Homework Statement





I Need to check if this is correct formula and need to do the rest by someone who knows. Thanks.
 
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Welcome to PF!

Hi CoffinSupply! Welcome to PF! :smile:
CoffinSupply said:
A novice skier, starting from rest, slides down a frictionless 35.00 incline whose vertical height is 185 m.How fast is she going when she reaches the bottom?

Yes, that's right … mg(185) = (1/2)mvf2

so vf = … ? :smile:
 


tiny-tim said:
Hi CoffinSupply! Welcome to PF! :smile:


Yes, that's right … mg(185) = (1/2)mvf2

so vf = … ? :smile:



Thanks, PF a great place!

vf =49.5 m/s ?
 
crossed out like terms. But how would you do it?
 
Can't you get the length of the slope using trigs and then then acceleration is g*sin35?
 
Can I get a complete solution to the problem done , if possible?