Conservation Of Mechanical Energy PROBLEM

AI Thread Summary
A novice skier slides down a frictionless 35-degree incline from a height of 185 meters, and the goal is to determine her speed at the bottom. The conservation of mechanical energy principle is applied, equating potential energy (mg(185)) to kinetic energy ((1/2)mvf²). Initial calculations suggest a final speed of 49.5 m/s, but there is uncertainty about the method used to arrive at this figure. Some participants discuss the possibility of incorporating trigonometry to find the slope length and acceleration. A complete solution to the problem is requested for clarity and accuracy.
CoffinSupply
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Homework Statement



A novice skier, starting from rest, slides down a frictionless 35.00 incline whose vertical height is 185 m.How fast is she going when she reaches the bottom?


Homework Equations



Need the rest of the solution.

The Attempt at a Solution



PICTURE SCAN: http://img528.imageshack.us/img528/8666/homeworkgi6.jpg

Homework Statement





I Need to check if this is correct formula and need to do the rest by someone who knows. Thanks.
 
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Welcome to PF!

Hi CoffinSupply! Welcome to PF! :smile:
CoffinSupply said:
A novice skier, starting from rest, slides down a frictionless 35.00 incline whose vertical height is 185 m.How fast is she going when she reaches the bottom?

Yes, that's right … mg(185) = (1/2)mvf2 …

so vf = … ? :smile:
 


tiny-tim said:
Hi CoffinSupply! Welcome to PF! :smile:


Yes, that's right … mg(185) = (1/2)mvf2 …

so vf = … ? :smile:



Thanks, PF a great place!

vf =49.5 m/s ?
 
CoffinSupply said:
Thanks, PF a great place!

vf =49.5 m/s ?

I don't think so …

how did you get that?
 
crossed out like terms. But how would you do it?
 
Can't you get the length of the slope using trigs and then then acceleration is g*sin35?
 
Can I get a complete solution to the problem done , if possible?
 

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