Conservation of Momentum of a shot bullet

AI Thread Summary
The problem involves calculating the recoil velocity of a gun when a bullet is fired, using the conservation of momentum principle. Given a 30 g bullet shot at +300 m/s from a 7.5 kg gun, the initial velocities of both objects are zero. The equation used is (m1 + m2)(v) = (m1v1) + (m2v2), leading to the calculation of the gun's recoil velocity. The solution shows that the recoil velocity of the gun is -1.2 m/s, indicating it moves in the opposite direction to the bullet. This confirms the conservation of momentum in the system.
Kennedy111
Messages
27
Reaction score
0

Homework Statement


If a 30 g bullet is shot with a velocity of +300 m/s from a 7.5 kg gun, what is the recoil velocity of the gun?

m1 = 0.03 kg
v1 = 300 m/s
m2 = 7.5 kg

Velocity initial for both objects is 0.0 m/s

Homework Equations



(m1 + m2)(v) = (m1v1) + (m2v2)


The Attempt at a Solution



0 = (0.03kg x 300m/s) + (7.5kg x v)
0 = 9kgm/s = (7.5kg x v)
-9kgm/s = 7.5 kg x v
v = -1.2 m/s
 
Physics news on Phys.org
Your attempt and solution look good.
 
Okay :) Thank you!
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top