Conservation of Momentum Question.

AI Thread Summary
The discussion centers on a conservation of momentum problem involving an airplane and a helicopter collision. Participants clarify the significance of the 20-degree angle above the horizon, emphasizing that it affects the vertical and horizontal components of the airplane's velocity. The conversation highlights the distinction between angles in a horizontal plane versus those in a vertical plane, which is crucial for solving the problem. Understanding these components is essential to accurately determine the final velocity of the helicopter post-collision. The complexity of the collision's dimensionality is acknowledged, indicating that it involves both vertical and horizontal considerations.
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Homework Statement



An 800 kg airplane traveling at a velocity of 120 m/s [30o N of E @ 20o above the horizon] collides with a stationary 1200 kg helicopter. If the velocity of the airplane after the collision is 65 m/s [40o N of E @ 60o above the horizon] what is the final velocity of the helicopter?

Homework Equations





The Attempt at a Solution



I don't understand what to do with the 20 degrees above the horizon part in both the parts.
 
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skg94 said:

Homework Statement



An 800 kg airplane traveling at a velocity of 120 m/s [30o N of E @ 20o above the horizon] collides with a stationary 1200 kg helicopter. If the velocity of the airplane after the collision is 65 m/s [40o N of E @ 60o above the horizon] what is the final velocity of the helicopter?

Homework Equations



The Attempt at a Solution



I don't understand what to do with the 20 degrees above the horizon part in both the parts.
First, choose a coordinate system.

The 20° angle should allow you to find a vertical and a horizontal component of the velocity of the airplane. Then break the horizontal component into an eastward component and a northward component.

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The way I read it, that is the plane's attitude. That is, it is not in level flight, but has a 20 degree angle up before the collision. The collision appears to take place in two dimensions, [STRIKE]in a vertical plane.[/STRIKE]
 
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Isnt, 20 degree above the horizon same as 20 degree N of E? 20 degrees from 0 right
 
Nope. Angles east or west of north are in a horizontal plane. Angles above or below the horizon (itself essentially a horizontal plane) are in a vertical plane.
 
tms said:
The way I read it, that is the plane's attitude. That is, it is not in level flight, but has a 20 degree angle up before the collision. The collision appears to take place in two dimensions, in a vertical plane.
The plane of the collision may be found from the airplane's velocity vector before the collision and it's velocity vector after the collision. This plane is not vertical.
 
SammyS said:
The plane of the collision may be found from the airplane's velocity vector before the collision and it's velocity vector after the collision. This plane is not vertical.

You're right, of course, and neither is it horizontal.
 
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