Constant velocity on frictional slope

AI Thread Summary
The discussion focuses on deriving the slope of a track where a sphere with a frictional coefficient u maintains a constant velocity v. Two approaches are examined: one using torque and Newton's second law, and the other using energy relations, leading to different expressions for acceleration. The key point is that when the sphere rolls without slipping, friction does not do work, allowing for energy conservation. The role of friction is highlighted as essential for enabling the sphere to roll by providing the necessary torque for rotation while maintaining mechanical energy conservation. Ultimately, the interplay between gravitational and frictional forces is crucial for understanding the rolling motion of the sphere.
Loren Booda
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Derive the slope of a track where a sphere having frictional coefficient u maintains constant velocity v.
 
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Show us what you've tried so far.
 
Tide,

It's not a homework problem (yet?), but I appreciate your response. I thought someone might have fun working out this nontrivial, simply stated puzzle.
 
If I use Torque = I * alpha and Newtons second law, I end up with the following for acceleration.

a = mg sin(theta) * r^2 /(I + mr^2) where I is w.r.t. the center of the rolling object.


If I use the energy relation (i.e Change in Energy = work done by the force), I get

a = g[2 sin (theta) + u cos(theta)] / ( 1 + I/mr^2)

I can't figure out where the discripancy is.
 
Gamma said:
If I use Torque = I * alpha and Newtons second law, I end up with the following for acceleration.

a = mg sin(theta) * r^2 /(I + mr^2) where I is w.r.t. the center of the rolling object.
Assuming the sphere rolls without slipping, this looks good.


If I use the energy relation (i.e Change in Energy = work done by the force), I get

a = g[2 sin (theta) + u cos(theta)] / ( 1 + I/mr^2)
Not sure what you did here. Realize that as long as the sphere rolls without slipping, the friction does no work.
 
Say that the sphere rolls down from top a distance x.

Final Energy Ef= 1/2 I w^2 + 1/2 m v^2 - mgx sin(theta). Of course if the energy is conserved I can show that accelaration 'a' is same as the first expression in my post which is correct for a rolling object down the hill.

So my question is what effect do the gravitational and frictional forces have on the rolling motion? What makes the ball roll?
 
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If there were no friction, the ball would slide down the hill without rolling. Friction exerts the torque (about the ball's center of mass) that makes the ball rotate as well as translate. As long as the friction is sufficient to make the ball roll without slipping, the friction does no work and mechanical energy is conserved. Friction enables the gravitational PE to be transformed into both rotational and translational KE.
 
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