Constrained Motion Problem: Understanding the First Step in the Solution

AI Thread Summary
The discussion revolves around understanding the first step in solving a constrained motion problem using Pythagoras' theorem, represented as Xa² + Xb² = L². The confusion arises when taking the time derivative of this equation, leading to the expression 2Xa(Xa(dot)) + 2Xb(Xb(dot)) = 0. Participants clarify that the time derivative involves applying the chain rule, which connects the variables to their time-dependent forms. The conversation emphasizes the importance of recognizing that the variables are functions of time, which is crucial for correctly applying derivatives. Overall, the thread highlights the application of fundamental calculus concepts in solving motion problems.
Clever_name
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Homework Statement



See attached picture.

Homework Equations


The Attempt at a Solution



I have the solution, but I'm puzzled by the first step in their solution, which reads

Xa^(2) + Xb^(2) = L^(2)

The solution provider then takes the time derivative of this expression which then produces

2Xa(Xa(dot))+2Xb(Xb(dot)) = 0

where Xa(dot) and Xb(dot) is the Xa or Xb symbol with a dot over it.

Thanks for you're assistance!
 

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Here is the solution if my explanation was confusing in any way.
 

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Any help would be greatly appreciated.
 
I don't understand what's puzzling you. The first line is just Pythagoras' theorem applied to the triangle of which AB is the hypotenuse.
 
The line below it, when taking the time derivative of the first line how do they end up with that expression?
 
If x = x(t), can you write down the expression for (d/dt)x2?
 
2x? or x(t)dx/dt = x(t)*x'(t)
 
How did you know that x was a function of time?
 
Clever_name said:
2x? or x(t)dx/dt = x(t)*x'(t)
No, but each answer you offer is half right. Do you know the chain rule?
 
  • #10
yep, i understand now haruspex, thanks!
 
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