Constructing a Bounded Non-Convergent Sequence in Complex Variables

desaila
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I can't think of how to title the problem I'm having, but this is what the course is called. Complex being imaginary numbers, ie z = a + ic where i is the sqrt of -1.

So here is the question that I have no idea where to start with:

Construct a sequence {zn} which is bounded and for which the successive
terms get increasingly closer, but which is not convergent. In other words,
{zn} must satisfy:
(i) For some B > 0, |zn| < B for every n = 1, 2,...
(ii) For every n, |zn+2 - zn+1| < |zn+1 - zn|.
(iii) {zn} diverges.
Note that the inequality in (ii) is strict. Make sure to prove that your
sequence satisfies all three parts.


n is a subscript of z.

Thanks in advance.
 
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Let tn=sum(1/i) for i=1 to n. Consider zn=exp(i*tn). Now you just have to do the proofs.
 
Thanks. On the same homework assignment, I have another problem but this is more with the question itself. What does this mean: limit of Arg z, as z approaches zero?
 
?? Just what it says! Or is the question rather "what does Arg z mean"?

Any complex number z= x+ iy can be written in polar form: z= r (cos(\theta)+ i sin(\theta) or simply as z= r e^{i\theta}. In either case Arg z= \theta.

Take a look at z= x+ ix. What is Arg z for all x? What is its limit as z (and so x) goes to 0?
Now look at z= x- ix. What is Arg z for all x? What is its limit as z (and so x) goes to 0?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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