Constructing Antiderivatives and areas

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SUMMARY

The discussion focuses on calculating areas divided by the curve \(\sqrt{x} + \sqrt{y} = \sqrt{a}\) within a square and determining the total cost of drilling an oil well based on fixed and marginal costs. The fixed cost for drilling is set at 1,000,000 riyals, with marginal costs defined by the equation \(C'(x) = 4000 + 10x\) riyals/meter. The total cost for drilling a well to a depth of \(x\) meters is calculated as \(1,000,000 + 10x\) riyals. Participants seek clarification on the interpretation of fixed costs and the application of definite integrals in these calculations.

PREREQUISITES
  • Understanding of definite integrals in calculus
  • Familiarity with fixed and marginal cost concepts in economics
  • Knowledge of area calculations related to curves and geometric shapes
  • Basic understanding of the Pythagorean theorem
NEXT STEPS
  • Study the application of definite integrals in calculating areas under curves
  • Learn about fixed and marginal costs in economic models
  • Explore geometric interpretations of curves and their intersections with shapes
  • Investigate the implications of cost functions in real-world drilling scenarios
USEFUL FOR

Students in calculus, economics, and engineering fields, particularly those working on optimization problems related to area calculations and cost analysis in drilling operations.

Jacobpm64
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Homework Statement


The origin and the point (a, a) are at opposite corners of a square. Calculate the ratio of the areas of the two parts into which the curve [tex]\sqrt{x} + \sqrt{y} = \sqrt{a}[/tex] divides the square.

Homework Equations


I'm sure there will be some use of A = bh. Perhaps maybe the pythagorean theorem if the square is cut exactly in half? I'm sure I'll be using a definite integral to find the areas.

The Attempt at a Solution


I have no clue where to go with this.

Homework Statement


In drilling an oil well, the total cost, C, consists of fixed costs (independent of the depth of the well) and marginal costs, which depend on depth; drilling becomes more expensive, per meter, deeper into the earth. Suppose the fixed costs are 1,000,000 riyals (the riyal is the unit of currency of Saudi Arabia), and the marginal costs are C'(x) = 4000 + 10x riyals/meter, where x is the depth in meters. Find the total cost of drilling a well x meters deep.

Homework Equations


I'm using I'll use a definite integral.

The Attempt at a Solution


Here's what I tried.
[tex]1,000,000 + \int (from 0 to x) of 4000 + 10x[/tex]
Evaluating that:
[tex]1,000,000 + [4000 + 10x - (4000 + 10(0) ) ][/tex]
[tex]1,000,000 + [4000 + 10x - 4000][/tex]
[tex]1,000,000 + 10x[/tex] riyals is the total cost.

I need some direction on the first one.. And I would like confirmation on the second one.
 
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For the first one, I would suggest drawing your two areas out.

For the second one, is a fixed cost supposed to mean a limit? In other words, does fixed cost mean that C(x)<=1,000,000? If, on the other hand, it means that there is some cost that automatically comes in when drilling even a millionth of a unit down then you did it right.
 

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