Continuity: Constant mass flow rate

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SUMMARY

The discussion focuses on calculating the number of capillaries in the human body based on the principle of continuity for incompressible fluids. Given the aorta's speed of 40 cm/s and radius of 1.1 cm, the cross-sectional area (Aa) is calculated as 3.8013 cm². The capillary speed is 0.07 cm/s with a radius of 6 x 10^-4 cm, yielding a cross-sectional area (Ac) of approximately 1.13097 x 10^-6 cm². Using the flow rate equation A1 x V1 = A2 x V2, the flow rate in the aorta is determined to be 152.05 cm³/s, leading to the equation A2 x V2 x N = 152.05 to find the number of capillaries (N).

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically the continuity equation.
  • Knowledge of cross-sectional area calculations using the formula A = πr².
  • Familiarity with the concept of incompressible fluids.
  • Basic algebra skills for solving equations.
NEXT STEPS
  • Study the derivation and applications of the continuity equation in fluid dynamics.
  • Learn about the properties of incompressible fluids and their implications in biological systems.
  • Explore advanced calculations involving flow rates in complex vascular systems.
  • Investigate the physiological significance of capillary density in human anatomy.
USEFUL FOR

Students in biology and physics, particularly those studying human anatomy, fluid dynamics, or cardiovascular physiology, will benefit from this discussion.

chantalprince
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Homework Statement



The aorta carries blood away from the heart at a speed of about 40 cm/s and has a radius of approx. 1.1cm. The aorta branches eventually into a large number of tiny capillaries that distribute the blood to the various body organs. In a capillary, the blood speed is approx. 0.07 cm/s, and the radius is about 6 x 10 -4 cm. Treat the blood as an incompressible flulid and use these data to determine the approx number of capillaries in the human body.



Homework Equations



I think: A1 x V1 = A2 x V2 and A = pi (r)^2


A = cross sectional area of tube
V= velocity




The Attempt at a Solution



I have figured out the areas of the cross sections of the capillary and the aorta.

I have labeled them: Ac and Aa respectively.

Ac= 1.13097 x 10^-6 cm^2

Aa= 3.8013 cm^2



I cannot figure out where to go with this information. It seems like I need to know a volume or a length of some sort.

Can anybody help me out please?

Thanks!
 
Last edited:
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Hint: The flow rate in must equal the flow rate out. The flow rate in is A_1 \cdot V_1 or about 152.05 \frac{cm^3}{s}.

The flow rate out must equal this, no matter how many paths it takes. Therefore A_2 \cdot V_2 \cdot N must equal 152.05, where N is the number of capillaries.

CS
 
Thank you very much Stewartcs!
 

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