Contour map and Intersection points

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SUMMARY

This discussion focuses on solving a mathematical problem involving contour maps and intersection points of geometric shapes. The function h(x,y) = -12 - 4x² + 16x - y² - 8y is analyzed to create a contour map, which reveals hyperbolas as the graph of constant values. The method of Lagrange multipliers is applied to find the closest point to the origin on the intersection of the plane 2y + 4z = 5 and the cone z² = 4x² + 4y², resulting in two intersection points: (0, 5/18, 5/9) and (0, 1/10, 1/20), with (0, 1/10, 1/20) being the closest to the origin.

PREREQUISITES
  • Understanding of contour maps in multivariable calculus
  • Familiarity with the method of Lagrange multipliers
  • Knowledge of geometric shapes such as planes and cones
  • Ability to compute gradients of functions
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  • Study the creation and interpretation of contour maps for functions of two variables
  • Learn the application of Lagrange multipliers in optimization problems
  • Explore the properties of hyperbolas and their equations
  • Investigate the geometric interpretation of intersection points in three-dimensional space
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Students and educators in mathematics, particularly those studying multivariable calculus, optimization techniques, and geometric analysis.

Arcon
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Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 
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Arcon said:

Homework Statement



(i) Drawing a contour map for the function h(x.y) = -12-4x^2+16x-y^2-8y
(ii) (Continuing from i) at the point (1,-1,7) which direction to move to have
the maximum increase in height?

(iii) Find the point closest to the origin on the curve of intersection of the
plane 2y + 4z = 5 and the cone z^2= 4x^2 + 4y^2.

Homework Equations



(i) z = -12-4x^2+16x-y^2-8y (then I am stuck)
Do you understand what a "contour map" IS? No, don't set h(x,y)= z. A contour map of a function of two variables is a graph is the xy-coordinates system. Set h(x,y)= equal to a number of different constants and graph each of them. (Looks to me like you will have a number of different hyperbolas with the same asymptotes.)

(iii) I got f = z <--(not sure if this is right),
g = 2y +4z = 5
and h = z^2= 4x^2 + 4y^2.

then gradient f = lambda * gradient g + mu * gradient h
Okay, that's the "Lagrange multiplier" method.

The Attempt at a Solution



then from some caluculation i got two intersection point of (0,5/18,5/9) and (0, 1/10, 1/20) with (0, 1/10, 1/20) the point closest to the origin.
 

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