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Lagrange optimization: cylinder and plane intersects,

  1. Apr 17, 2016 #1
    1. The problem statement, all variables and given/known data

    The cylinder x^2 + y^2 = 1 intersects the plane x + z = 1 in an ellipse. Find the point on the ellipse furthest from the origin.

    2. Relevant equations

    $f(x) = x^2 + y^2 + z^2$

    $h(x) = x^2 + y^2 = 1$

    $g(x) = x + z = 1$

    3. The attempt at a solution

    $\langle 2x, 2y, 2z \rangle = \lambda\langle2x, 2y,0\rangle + \mu\langle1,0,1\rangle$

    This results in the equations:

    $2x = 2x\lambda + \mu$

    $2y = 2y\lambda$

    $2z = \mu$

    Then $\lambda = 1$, then $2x = 2x + \mu$, then $0 = \mu$, so then $z = 0$.

    Then $x + z = 1$, so $x = 1$.

    And then $1^2 + y^2 = 1$, so $y = 0$, so then I conclude that the point where this ellipse is furthest from the origin is $(1,0,0)$.

    This is wrong. The answer should be $(-1,0,2)$
     
  2. jcsd
  3. Apr 17, 2016 #2

    haruspex

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    You'll have a much better chance of replies if you fix up the Latex. You need to double the dollar signs, or if you don't want an equation on a line by itself replace the dollar sign with a double hash(#).
     
  4. Apr 18, 2016 #3

    Ray Vickson

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    The equation ##2y = 2y \lambda## implies either ##\lambda = 1## or ##y = 0##.

    Note how my LaTeX comes out properly, unlike yours. That is because I used "# # ... # #", but with no space between the two #'s at the start and the end. Had I used $...$ instead it would have come out a mess, like yours. LaTeX/TeX works a bit differently on this Forum than it does in native form.
     
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