Contribution of Distrance and Speed on Time Taken

  • Thread starter Thread starter harrycool
  • Start date Start date
  • Tags Tags
    Speed Time
harrycool
Messages
1
Reaction score
0
In Scenario 1. I travel 1000 KMs @ 100 KM/Hr. I reach my destination in 10 Hours.
In Scenario 2. I travel 600 KMs @ 80 KM/Hr. I reach my destination in 7.5 Hours.

How much time do I save due to reduction in distance and how much time is wasted due to reduction in speed?

If I do not change the speed but only change distance (600 KM, 100 KM/Hr), I get 4 hours saved. If I do not change the distance but only the speed (1000KM, 80 KM/Hr), I get 2.5 hours extra. -4 + 2.5 = -1.5. However, in total, I have saved 2.5 hours. So how do I find the contribution of distance and speed in my overall time savings?
 
Mathematics news on Phys.org
Welcome to PF;
So how do I find the contribution of distance and speed in my overall time savings?
afaik, there is no standard way to compare them. Fortunately, the question does not ask you to.
 
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles. In Dirac’s Principles of Quantum Mechanics published in 1930 he introduced a “convenient notation” he referred to as a “delta function” which he treated as a continuum analog to the discrete Kronecker delta. The Kronecker delta is simply the indexed components of the identity operator in matrix algebra Source: https://www.physicsforums.com/insights/what-exactly-is-diracs-delta-function/ by...
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
I'm interested to know whether the equation $$1 = 2 - \frac{1}{2 - \frac{1}{2 - \cdots}}$$ is true or not. It can be shown easily that if the continued fraction converges, it cannot converge to anything else than 1. It seems that if the continued fraction converges, the convergence is very slow. The apparent slowness of the convergence makes it difficult to estimate the presence of true convergence numerically. At the moment I don't know whether this converges or not.
Back
Top