- #1

aashish.v

- 13

- 0

I need to prove that it diverges in forward direction but converges in backward direction.

I am unable to find any method, kindly suggest.

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- Thread starter aashish.v
- Start date

- #1

aashish.v

- 13

- 0

I need to prove that it diverges in forward direction but converges in backward direction.

I am unable to find any method, kindly suggest.

- #2

camjohn

- 80

- 0

Are you sure that you typed the function correctly?

- #3

aashish.v

- 13

- 0

for forward direction we can re-write it this way..

J(n)=2*(n-1)*J(n-1)-J(n-2)

and for backward propogation...

J(n)=2*(n+1)*J(n+1)-J(n+2)

- #4

aashish.v

- 13

- 0

view this to avoid any ambiguity

- #5

Ray Vickson

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I need to prove that it diverges in forward direction but converges in backward direction.

I am unable to find any method, kindly suggest.

You need to show your work.

RGV

- #6

aashish.v

- 13

- 0

You need to show your work.

RGV

The typical approach shown in text is to show that if the solution of such function truns out to be in form of

[itex]C.λ^n[/itex] then we can say that such recursive function diverges, I have tried the same approach for the problem but the λ I am getting turns out to be function of n.

I can scan and upload my work if you wish.

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