Convergence of an alternating series

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SUMMARY

The discussion centers on the convergence of an alternating series defined by the sequence with the n-th term denoted as ##u_n##. It establishes that if the limit of the sum of the first 2m terms, ##S_{2m}##, approaches zero as N approaches infinity, the series converges. However, the proof is critiqued for lacking clarity, particularly in addressing the requirement that the terms must be alternating and decreasing in magnitude. The Sandwich Theorem is suggested as a method to demonstrate that the partial sums are bounded between two values converging to the same limit.

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Consider a sequence with the ##n^{th}## term ##u_n##. Let ##S_{2m}## be the sum of the ##2m## terms starting from ##u_N## for some ##N\geq1##.

If ##\lim_{N\rightarrow\infty}S_{2m}=0## for all ##m##, then the series converges. Why?

This is not explained in the following proof:
Screen Shot 2016-06-11 at 1.20.39 am.png

Screen Shot 2016-06-11 at 1.20.51 am.png
 
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Happiness said:
Consider a sequence with the ##n^{th}## term ##u_n##. Let ##S_{2m}## be the sum of the ##2m## terms starting from ##u_N## for some ##N\geq1##.

If ##\lim_{N\rightarrow\infty}S_{2m}=0## for all ##m##, then the series converges. Why?
This is not true, consider ##u_n=(-1)^n##. You also have to add that un are alternating and decreasing in magnitude.

The proof looks a bit sloppy, but you can use a similar approach to show that the partial sum is always between two numbers that approach the same limit. Sandwich theorem.
 
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