Convergence of an alternating series

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Consider a sequence with the ##n^{th}## term ##u_n##. Let ##S_{2m}## be the sum of the ##2m## terms starting from ##u_N## for some ##N\geq1##.

If ##\lim_{N\rightarrow\infty}S_{2m}=0## for all ##m##, then the series converges. Why?

This is not explained in the following proof:
Printed mathematical text proving convergence of an alternating series: it defines the series with terms (-1)^(n+1) u_n, states the conditions u_n tends to 0 and u_n less than u_(n-1), then bounds the partial sums S_2m between 0 and u_N.

Printed text fragment from a calculus proof: the partial sum is always less than u_N for all m, and u_n tends to 0 as n tends to infinity, so the alternating series converges; an analogous proof works when N is even.
 
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Happiness said:
Consider a sequence with the ##n^{th}## term ##u_n##. Let ##S_{2m}## be the sum of the ##2m## terms starting from ##u_N## for some ##N\geq1##.

If ##\lim_{N\rightarrow\infty}S_{2m}=0## for all ##m##, then the series converges. Why?
This is not true, consider ##u_n=(-1)^n##. You also have to add that un are alternating and decreasing in magnitude.

The proof looks a bit sloppy, but you can use a similar approach to show that the partial sum is always between two numbers that approach the same limit. Sandwich theorem.
 
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