Convergent or Divegent Series?

[iatnogpitw]

Homework Statement

\sum{(ln(k))/(\sqrt{k+2})}, with k starting at 1 and going to \infty

Homework Equations

Does this series converge or diverge? Be sure to explain what tests were used and why they are applicable.

The Attempt at a Solution

Okay, my TA got that this diverges, but I got that it converges by simply taking the limit as k goes to \infty and applying L'Hopital's rule. I also plugged the function into my calculator and it seems to converge at y=0, which is corroborates what I got with L'Hopitals rule. What did you guys get? Any help is greatly appreciated.

 

[Office_Shredder]

It looks like you proved the individual terms go to 0, which isn't what you're trying to do. The definition of a series is you take the limit of the partial sums. And where does y come into the series?

Try comparing the series to \frac{1}{\sqrt{k+2}} whose convergence/divergence is easier to find

 

[iatnogpitw]

Right, I forgot about the partial sums. Thanks, that helped a lot. But isn't 1/(\sqrt{k+2}) smaller than (ln(k))/(\sqrt{k+2})?

 

[Mark44]

Right, I forgot about the partial sums. Thanks, that helped a lot. But isn't 1/(\sqrt{k+2}) smaller than (ln(k))/(\sqrt{k+2})?

Yeah, it is. You've been handed a clue for free. If you can say something about what \sum 1/(\sqrt{k+2}) does, then maybe you will know something about the series you're really interested in.