Converting Cartesian to Polar Coordinates: How Do We Get r and Theta?

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To convert the Cartesian equation y = 3x + 4 into polar coordinates, substitute x with r cos(θ) and y with r sin(θ). This leads to the equation r sin(θ) = 3(r cos(θ)) + 4. Rearranging gives r(sin(θ) - 3 cos(θ)) = 4, allowing for r to be isolated. The goal is to express r solely in terms of θ, resulting in the final polar form. This method effectively transforms Cartesian coordinates into polar coordinates.
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Homework Statement


Write equation in polar form. y=3x+4


Homework Equations


x^2 + y^2 = r^2
x = rcos(theta)
y = rsin(theta)
tan(theta) = y/x


The Attempt at a Solution



Square both sides...
y^2 = 9x^2 + 24x + 16

r^2 - x^2 = 9x^2 +24x +16

r^2 = 10x^2 + 24x + 16

And that's where I got stuck...
 
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Don't do it like that. Substitute the polar form of x and y into your equation... and you'll be done.
 
Replace EVERY x with r cos(\thet and EVERY y with r sin(\theta)
 
What is your goal in converting from Cartesian to polar coordinates? You want to get a function that is:
r = a bunch of theta junk

So how do we turn y=3x+4 into an equation of nothing but r’s and theta’s? We use the two substations you have, then we get r all by it self on one side.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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